> two floats A and B should be compared with this algorithm :
>
> diff=A-B
> if (diff>tolerance) then A>B
> else if (diff<-tolerance) then A<B
> else A = B
You could define a new collation sequence to do all that. However, it's
difficult to say what will happen when you have three numbers A, B and
C such that A==B and B==C but A!=C. This will cause the occasional oddity.
But if you know for some reason this will never happen, everything will
work fine. "Know"....
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