The table contains a single row with a single column that contains a string.
That doesn't make it a string. It's still a table. When you say "select ... from table" it doesn't matter where the table came from, it's still an operation on a table. You are not performing "select ... from 'tab1';", you're performing "select ... from unnamed-table" where "unnamed-table" contains one row containing 'tab1'. The result of *that* select is yet another unnamed table that the sqlite3 shell displays for you. Even if you perform select * from (select * from (select * from ( ... ) ) The result is still a table. Select is not an indirection operator like accessing an element of an array or a structure. On 2017-11-05, at 05:39, Klaus Maas <k...@maasser.eu> wrote: > Yes, correct. > > But the contents of the returned table are not objects, but merely values. > > In this case the returned table contains a single string value .... which > happens to be the name of a table, but it is not the table. > > Or do I get this wrong? _______________________________________________ sqlite-users mailing list email@example.com http://mailinglists.sqlite.org/cgi-bin/mailman/listinfo/sqlite-users