On 2018/03/21 5:30 PM, Ron Watkins wrote:
I have a table which contains a datetime column:
table|foo|foo|2|CREATE TABLE foo (
dttm datetime not null
i int not null
)
I want to select out the max(i) value for each day where there are multiple
records per day.
select date(dttm) dt,max(i) from foo group by dt order by 1;
However, it’s returning only 1 row, with no date column shown. How can I
get an actual “date” listed in the first column, and also get 1 row per
“date” value.
I fear I might be missing something obvious, but wouldn't this just do
the job?:
SELECT date(dttm) AS dt, max(i)
FROM foo
GROUP BY date(dttm)
If you still get only 1 row, it means there is only 1 date value in all
the rows in your table.
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