It is hard for me to tell which is index, which is value and so forth in your 
example, but how about this single select:

SELECT DISTINCT key, value FROM theTable;

This lists all distinct key-value possibilities. Or,

SELECT key, value FROM (SELECT DISTINCT key, value FROM theTable) 
GROUP BY key, value HAVING count() > 1;

This lists all key-value pairs with more than one value for the key. 

Roman

________________________________________
From: sqlite-users [sqlite-users-boun...@mailinglists.sqlite.org] on behalf of 
David Raymond [david.raym...@tomtom.com]
Sent: Thursday, October 11, 2018 12:23 PM
To: SQLite mailing list
Subject: Re: [sqlite] Find key,value duplicates but with differing values

Maybe

...
group by partId, name
having count(distinct xmd.value) > 1;

?


-----Original Message-----
From: sqlite-users [mailto:sqlite-users-boun...@mailinglists.sqlite.org] On 
Behalf Of Dominique Devienne
Sent: Thursday, October 11, 2018 12:00 PM
To: General Discussion of SQLite Database
Subject: [sqlite] Find key,value duplicates but with differing values

I can find duplicates fine:

select xmd.partId, parts.title, xmd.name,
       count(*) "#dupplicates",
       group_concat(xmd.value) "values",
       group_concat(xmd.idx) "indexes"
  from extra_meta_data xmd
  join parts on parts.id = xmd.partId
  group by partId, name
 having "#dupplicates" > 1;

but most actual duplicates have the same value, so are harmless.
so I'd like to select only the xmd.name rows which have differing values.

Knowing that there can be more than 2 duplicates, i.e. a slef-join is not
enough I think.
Any hints on how to go about this problem please? Thanks, --DD
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