heribert wrote:
> I've a tree with doubly linked items. I want to get all siblings of a tree
> node.
If you want them in order, you have to walk through the linked list:
WITH SiblingsOf3 AS (
SELECT *
FROM Tree
WHERE ParentIDX = (SELECT ParentIDX
FROM Tree
WHERE ID = 3)
AND PrevIDX IS NULL
UNION ALL
SELECT Tree.*
FROM Tree
JOIN SiblingsOf3 ON SiblingsOf3.NextIDX = Tree.ID
)
SELECT * FROM SiblingsOf3;
Regards,
Clemens
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