It doesn't look like my attachment worked, so here is the code:
------------------------------------------------------------
#include <stdio.h>
#include <sqlite3.h>
int
main (void)
{
int i;
sqlite3_stmt *stmt = NULL;
sqlite3 *db = NULL;
int vals[] = { 4, 5, 6 };
sqlite3_open_v2("test.db", &db, SQLITE_OPEN_READONLY, NULL);
sqlite3_prepare_v2(db, "SELECT id, value FROM test WHERE value = ?", -1,
&stmt, NULL);
for (i = 0; i < 3; i++) {
sqlite3_bind_int64(stmt, 1, vals[i]);
printf("BOUND %d\n", vals[i]);
sqlite3_reset(stmt);
while (sqlite3_step(stmt) == SQLITE_ROW) {
printf("FOUND %lld,%lld\n", sqlite3_column_int64(stmt, 0),
sqlite3_column_int64(stmt, 1));
}
}
sqlite3_finalize(stmt);
sqlite3_close_v2(db);
return 0;
}
------------------------------------------------------------
On 5/6/19 11:04 pm, Josef Barnes wrote:
Hi,
We've come across a situation where we think there is a bug in the
sqlite3_reset() function. The documentation states:
"Any SQL statement variables that had values bound to them using the
sqlite3_bind_*() API retain their values"
The behaviour we are seeing appears to contradict this statement. I've
attached a very simple example of searching for a few rows in a
database. To run the example, create a database (test.db) with the
following schema:
CREATE table test ( id INTEGER PRIMARY KEY, value INTEGER NOT NULL );
INSERT INTO test VALUES ( 1, 4 );
INSERT INTO test VALUES ( 2, 5 );
INSERT INTO test VALUES ( 3, 6 );
In the example code, notice that the call to sqlite3_reset() comes
after the call to sqlite3_bind_int64(). When running the example, it
will return the first row all three times. It seems that the call to
sqlite3_reset() actually resets the binded variable to the value it
had at the last call to sqlite3_step().
Is this a bug? Or is it intended behaviour? If it's intended, I
recommend updating the documentation to be clear about this behaviour.
Thanks for any insight anyone can provide.
Joe
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