On 9/10/2019 7:05 AM, Keith Medcalf wrote:
select value, round((julianday(value) - julianday('00:00:00')) * 86400.0, 3) from test;
Another possibility: strftime('%s', '1970-01-01 ' || value) -- Igor Tandetnik _______________________________________________ sqlite-users mailing list sqlite-users@mailinglists.sqlite.org http://mailinglists.sqlite.org/cgi-bin/mailman/listinfo/sqlite-users