Dnia wtorek, 5 lutego 2008, Gerry Snyder napisaĆ: > P Kishor wrote: > > sqlite> select t.* from test t join (select name, max(weight) as m > > from test group by name) w on t.weight = w.m and t.name = w.name; > [...] > > select * from test join (select name as n, max(weight) as m from test > group by name) where name = n and weight = m;
Thank You very much. I know, that GROUP BY should have all SELECT fields, but thought, that he will choose row with MAX(), not the last row in dataset. With the problem of "ties" I suppose, the easiest (but not SQL) way to make for() loop for each group (SELECT DISTINCT name), and do SELECT * FROM test WHERE name='{loop name}' ORDER BY weight DESC LIMIT 1 vip; _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users