Am 13.11.2009 um 09:25 schrieb Keith Roberts:
> On Fri, 13 Nov 2009, Artur Reilin wrote:
>
>> To: General Discussion of SQLite Database <[email protected]>
>> From: Artur Reilin <[email protected]>
>> Subject: Re: [sqlite] image upload to db trouble
>>
>>> //echo $images;
>>> $db = new PDO('sqlite: database.sqlite3');
>>>
>>> $con = sqlite_open('sqlite: database.sqlite3');
>>> if (!$con)
>>> {
>>> die('Could not connect: ' . mysql_error());
>>> }
>>
>> why you first make a new db opject and then open an connection to the
>> database? new PDO sqlite already open an connection .. as i am right.
>>
>> and why mysql_error() ?
>>
>>>
>>> $db->query('sqlite: database.sqlite3', $con);
>>>
>>> $db->query ("INSERT INTO images (id, images, info, url)
>>> VALUES ('$i', '$images', '$info', '$url')");
>>>
>>> $db->query("DELETE FROM images WHERE id='$i'");
>>> }
>>
>> AS i know, if you want to put images in your db you need blob
>> columns and
>> these are supported in sqlite3. or i understand something wrong?
>
> There's no need to save the actual image in the sqlite
> database, as that could slow things like SELECT statements
> down.
>
> Another way is to move the image file to a certain
> directory. Then store only the location of the image file in
> the sqlite DB.
>
> If you move the sqlite DB, then just make sure the directory
> of images also goes with it.
AFAICS from the original source, this is already what the code is
supposed to do:
> if (move_uploaded_file($_FILES['userfile']['tmp_name'][$i],
> $uploadfile))
> {
>
> $success++;
> $info= $_POST[desc.$i];
> $images=$uploadfile;
> $url=$_POST[textfield.$i];
> ...
> $db->query ("INSERT INTO images (id, images, info, url) VALUES
> ('$i', '$images', '$info', '$url')");
> ...
> }
Thus, $images is just a string containing the path to the moved upload
file...
However, there's a couple of statements in the code that I don't know
what to make of:
(1) as pointed out earlier, the DELETE statement removes the record
immediately after INSERTing
(2) $db = new PDO('sqlite: database.sqlite3'); -> this will attempt
to open a connection to the database file "database.sqlite3" in which
directory? Did you check that this call succeeded??? You may need to
use an absolute path here...
(3) $con = sqlite_open('sqlite: database.sqlite3'); -> wouldn't this
open just another sqlite database connection via a different mechanism?
(4) $db->query('sqlite: database.sqlite3', $con); -> what is this
supposed to do?
Did you verify that your query calls actually succeeded?
I would
(a) check that $db != null
(b) check that the query calls actually worked (PDO::query() returns
a PDOStatement object, or FALSE on failure.)
</jum>
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