Doesn't it return an array of sqlite3_stmt pointers? If you prepare this statement:
"BEGIN; UPDATE something SET this='that'; COMMIT;" Then the array will contain the statement handles for the three statements BEGIN, UPDATe and COMMIT. /Jonas On Tue, Mar 9, 2010 at 7:17 PM, Igor Tandetnik <itandet...@mvps.org> wrote: > Ed Curren <ecur...@hotmail.com> wrote: >> According to the documentation the function prototype for >> sqlite3_prepare_v2 is the following: >> >> >> >> int sqlite3_prepare(sqlite3 *db, const char *zSql, int nByte, >> sqlite3_stmt **ppStmt, const char **pzTail); > > Note two stars in sqlite3_stmt **ppStmt. You pass a pointer to sqlite3_stmt* > (whose previous value is irrelevant and will be overwritten), and the > function fills it with the handle. Like this: > > sqlite3_stmt* stmt = NULL; > sqlite3_prepare(db, "select * from mytable;", -1, &stmt, NULL); > // Now stmt contains statement handle. > > In other words, it's an out parameter. > > Igor Tandetnik > > > _______________________________________________ > sqlite-users mailing list > sqlite-users@sqlite.org > http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users > _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users
