This one doesn't seem to return the desired result, instead it returned a
blank line?

On Wed, Sep 29, 2010 at 12:40 PM, David Bicking <[email protected]> wrote:

> How about trying
>
> select distinct datetime(date,'%Y') as year from data;
>
> David
>
> --- On Wed, 9/29/10, J. Bobby Lopez <[email protected]> wrote:
>
> > From: J. Bobby Lopez <[email protected]>
> > Subject: [sqlite] Getting unique years from a timestamp column
> > To: [email protected]
> > Date: Wednesday, September 29, 2010, 12:34 PM
> > Hello,
> >
> > I'm looking to do something completely in SQLite, without
> > the assistance of
> > Perl.
> >
> > The problem is this:
> >
> > I have a table with a text column, and the column contains
> > unix timestamps.
> > I would like to get a list of the unique years from that
> > timestamp column.
> >
> > Here's what the raw dataset looks like:
> >
> > 1|blopez|somekinda.log|2010-07-10
> > 13:21:10|10.100.0.1|make_db.pl
> > |usage_reporter()
> > 2|blopez|somekinda.log|2010-09-28
> > 06:18:51|10.100.0.1|make_db.pl
> > |usage_reporter()
> > 3|blopez|somekinda.log|2010-06-28
> > 17:58:37|10.100.0.1|make_db.pl
> > |usage_reporter()
> > 4|blopez|somekinda.log|2011-06-28
> > 17:58:37|10.100.0.1|make_db.pl
> > |usage_reporter()
> >
> > What I'd like to do is write a query that would return
> > "2010" and "2011",
> > the two unique years in the listing.
> >
> > It's pretty easy to get all records which match a single
> > year, for example:
> >
> > SELECT id FROM data WHERE datetime(date) LIKE '2010%';
> >
> > I'm sure I could use a BEGIN/COMMIT block and test for each
> > year
> > individually, but I don't want to hard-code the year that
> > I'm looking for,
> > if you get my meaning.
> >
> > Any assistance on this would be appreciated.  Thanks!
> >
> > Bobby
> > _______________________________________________
> > sqlite-users mailing list
> > [email protected]
> > http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users
> >
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