Quoth Eugene N <neverov.biks.0...@gmail.com>, on 2011-03-13 18:14:49 +0200: > uchar* pblah[1]; > > pblah[0] = (uchar*)malloc(10); > > pblah[1] = (uchar*)malloc(10); // notice the order > > sqlite3* db;
Your C code is broken. pblah is an array of 1 element, which is accessible (among other ways) as pblah[0]. pblah[1] is out of bounds, and depending on how the compiler allocates those vars it may wind up aliasing the db pointer. This is not an SQLite problem. ---> Drake Wilson _______________________________________________ sqlite-users mailing list sqlite-users@sqlite.org http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users
