When I try to create a table that already exists inside a database I obtain the error message: "table xyz already exists" and the error code is 1. Is there a way to obtain a more specific error code that can programmatically inform me that the object is already inside the db? Seems like also Extended Result Codes do not cover this case.
Please help. Thanks let me know. -- Marco Bambini http://www.sqlabs.com _______________________________________________ sqlite-users mailing list [email protected] http://sqlite.org:8080/cgi-bin/mailman/listinfo/sqlite-users
