On 2 Jul 2012, at 17:52, Nico Williams wrote:
> So an IPv4 CIDR block like 10.2.93.128/25 would encode as x'0A025D81'
> and 10.2.93.128/26 as x'0A025D82', and so on, with 10.2.93.128/32
> encoded as x'0A025D8000' (that's 5 bytes). That is, IPv4 addresses
> would require one more byte than usual.
You're missing some cases which I would find indispensible.
I have a trip tomorrow. I may be able to use the plane time
to think about your examples above and to put together some
complementary ones of my own.
/Niall
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