Probably you are using a variant of the printf() function to generate your 
statement and it is interpreting the %m as strerror(errno)  (see man 3 printf), 
whereas it is ignoring %' (thousands separator for decimal conversions) either 
because it does not support this conversion or it is missing the conversion 
specifier.

Try inserting (3,'icka') into your table.

If it works in the shell but not in your program, then it is nearly always your 
program that is to blame.

-----Ursprüngliche Nachricht-----
Von: Micka [mailto:mickamus...@gmail.com]
Gesendet: Dienstag, 03. Juni 2014 08:58
An: sqlite-users@sqlite.org
Betreff: [sqlite] Like and percent character

Hi,

I'm having trouble with the percent character .....


By example in my table I have :

id name
1 micka
2 mickael

I would like to do that :

Select * from table name where name LIKE '%micka%'

with my linux c program, the result is 0

but with the sqlite3 command program it works ....

I also tested this :

Select * from table name where name LIKE 'micka%'

and this time, it works in my linux c program ...

I'm using the last package of sqlite3-dev ...
https://packages.debian.org/wheezy/sqlite3

Why ?

Thx you !
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