If you just need them in descending order, i.e. not an arbitrary order, 
then "order by rec desc" will work.

On 5/20/2011 7:23 AM, jose isaias cabrera wrote:
> "Martin Engelschalk" on Friday, May 20, 2011 10:21 AM wrote...
>
>
>> Hi,
>>
>> to order, you have to use "order by". In that case, however, it gets
>> complicated.
>>
>> SELECT * FROM Jobs WHERE rec IN (87, 33, 27,2, 1)
>> order by case rec when 87 then 1
>>                    when 33 then 2
>>                    when 37 then 3
>>                    when 2 then 4
>>                    when 1 then 5
>>            end;
>>
>> Martin
> Thanks, this will work.
>
>> Am 20.05.2011 15:55, schrieb jose isaias cabrera:
>>> "Oliver Peters" on Friday, May 20, 2011 9:47 AM wrote...
>>>
>>>
>>>> jose isaias cabrera<cabrera@...>   writes:
>>>>
>>>>> Greetings.
>>>>>
>>>>> I would like to get a bunch of records of IDs that I already know. For
>>>>> example, this table called Jobs,
>>>>> rec,...,data,...
>>>>> 1,...,aaa,...
>>>>> 2,...,zzz,...
>>>>> ...
>>>>> ...
>>>>> 99,...,azz,...
>>>>>
>>>> [...]
>>>>
>>>>
>>>> What about
>>>>
>>>> SELECT *
>>>> FROM table
>>>> WHERE id BETWEEN 1 AND 99;
>>>>
>>>> greetings
>>>> Oliver
>>> I presented a bad example, Oliver.  My apologies.  I want specific IDs,
>>> so
>>> the WHERE rec IN (1,2,27,33,87) works perfectly.  However, I have one
>>> last
>>> question: if I do this call,
>>>
>>> SELECT * FROM Jobs WHERE rec IN (87, 33, 27,2, 1)
>>>
>>> the result is 1, 2, 27, 33, 87.  How can I get that specific order?
>>>
>>> thanks,
>>>
>>> josé
>>>
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