Hi, On Thursday 02 March 2006 07:48, Stuart Hungerford wrote: > What I can't work out for sure is whether there's a standard > way of doing this successfully, or whether it's just > impossible. As far as i read the code you havent to do anything special. Just define your sqlobject class as normal with the name of the view. That should work. Logically only if you dont modify/insert data. This propably can be made working, but this is database side of work (Look for "Rule"'s in the Postgresql documentation")
Andres
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