On Tue, 8 May 2007 at 18:27, Christopher Singley wrote: > On Tuesday 08 May 2007 12:08, Jim Steil wrote: >> What I'm >> trying to do is get a list of requisitions sorted by plant name. > > Why not get a list of requisitions, and then sort it by plant name? > > list(Requisition.select()).sort(key = lambda x: x.plant.name)
Because he's trying to do it in a context where things are a lot simpler if the result is a SelectResults object. I know because I read his earlier post on the TurboGears mailing list :) --David ------------------------------------------------------------------------- This SF.net email is sponsored by DB2 Express Download DB2 Express C - the FREE version of DB2 express and take control of your XML. No limits. Just data. Click to get it now. http://sourceforge.net/powerbar/db2/ _______________________________________________ sqlobject-discuss mailing list sqlobject-discuss@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/sqlobject-discuss
