On Thu, Jun 21, 2012 at 10:45:40PM +0200, Petr Jake?? <petr.ja...@tpc.cz> wrote:
> I am sure Oleg is reading this and
> gives his comments about the issue.
I think there have to be a way to generate id's for a complex VIEW
by, e.g., combining id's into a string with a delimiter; SQLObject
supports string id. Or calculating a hash value of that combined id and
using the hash as the id.
Oleg.
--
Oleg Broytman http://phdru.name/ p...@phdru.name
Programmers don't die, they just GOSUB without RETURN.
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