On 02/07/2017 02:21 AM, Oleg Broytman wrote:
>
> 'name' in SQLObject is a pythonic name of column; if you want to
> provide a database name it's called 'dbName':
>
> class User(sqlobject.SQLObject):
>
> class sqlmeta:
> table = 'tbl_user'
> idName = 'user_id'
>
> user_section = sqlobject.ForeignKey('Section', dbName='user_section')
>
> Also you have to know that translation from names to dbName's is
> performed by an instance of Style. See styles.py and
> tests/test_style.py. If you don't want to submit to default SQLObject
> style (which, among other things, adds '_id' to ForeignKey's) and don't
> want to provide dbName for every column you can create your own Style
> and override the default.
>
Got it ! Nice answer.
Thx
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