Got it working by setting:
$var(account)=$(au{s.select,0,-}{s.toupper}) + "-" + $(au{s.select,1,-});
Thanks
În mie., 10 iul. 2019 la 15:13, Ilie Soltanici <[email protected]> a
scris:
> Hello,
>
> Could someone help me to set a variable as a string in Kamailio?
>
> At the moment i'm using the following statement:
>
> *$var(account)=$(au{s.substr,0,8}); *
> *xlogl("L_INFO", "[1234] Account: $var(* *account*
> *)\n");*
>
> which is working fine, but i need to change it into:
>
> *$var(account)=$(au{s.select,0,-}{s.toupper})-$(au{s.select,1,-});*
>
> By doing this I'm getting the error:
>
>
>
> *[core/rvalue.c:1007]: rval_get_int(): automatic string to int conversion
> for "AT" failed[core/rvalue.c:1912]: rval_expr_eval_int(): rval expression
> conversion to int failed (729,30-729,59)*
>
> I tried also:
>
> *$var(account)="" + "$(au{s.select,0,-}{s.toupper})-$(au{s.select,1,-})";*
>
> But, then I'm getting:
>
> *Account = $(au{s.select,0,-}{s.toupper})-$(au{s.select,1,-})*
> instead of the value.
>
> What is the correct way to set it?
>
> Thank you.
>
_______________________________________________
Kamailio (SER) - Users Mailing List
[email protected]
https://lists.kamailio.org/cgi-bin/mailman/listinfo/sr-users
