I knew there had to be a better option! Thanks Federico :)
Best regards,
Joel.
----- Original Message -----
> From: "Federico Cabiddu" <federico.cabi...@gmail.com>
> To: "Kamailio (SER) - Users Mailing List" <sr-users@lists.sip-router.org>
> Sent: Friday, June 24, 2016 11:45:50 PM
> Subject: Re: [SR-Users] Parsing diversion headers correctly
> Hi Joel,
> to the extract the username part of the last Diversion header you could modify
> your last example like this:
> $(hdr(Diversion)[-1]{nameaddr.uri}{uri.user})
> Regards,
> Federico
> On Sat, Jun 25, 2016 at 3:23 AM, Joel Serrano | VOZELIA < j...@vozelia.com >
> wrote:
>> Hi,
>> If you receive an INVITE with 2 diversion headers such as (in this order):
>> Diversion: <sip:9975@X.X.X.X:5060>;privacy=off;screen=no; reason=user-busy;
>> counter=1
>> Diversion: <sip:1234567890@Z.Z.Z.Z:5060>;privacy=off;screen=no;
>> reason=unknown;
>> counter=1
>> How is a nice way of extracting the user part from the URI of the last one?
>> (in
>> this case: 1234567890)
>> Problems I have found:
>> $(di{uri.user}) ---> Give mes the user part of the URI of the first header,
>> in
>> this case: 9975
>> Is there a way to tell $di to get its value from the last header instead of
>> the
>> first one?
>> This example works:
>> $(hdr(Diversion)[-1]{ param.name ,0}{s.strip,1}{s.striptail,1}{uri.user})
>> But I think it is very hacky...
>> Any better approach anyone can suggest me?
>> Thanks in advance.
>> Best regards,
>> Joel.
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