Hello,
You can use {uri.host}
<http://www.kamailio.org/wiki/cookbooks/5.0.x/transformations#urihost>
transformation.
Regards,
Szabolcs
2017-03-22 18:23 GMT+01:00 Ali Taher <ata...@vanrise.com>:
> Hello everyone,
>
>
>
> I’m trying to get the host part from the contact header in the sip invite
> packet.
>
>
>
> Following is the contact header format:
>
> Contact: <sip:user_name@192.168.1.1:5060>
>
>
>
> What I want as result is 192.168.1.1
>
>
>
> I searched among the pseudovairables and found $ct variable which
> reference to the body of contact header. (<sip:user_name@192.168.1.1:5060
> >)
>
>
>
> Is there a way to get directly the host (192.168.1.1) without applying
> transformation at the level of $ct.
>
> If not what transformation can achieve it.
>
>
>
> Thanks in advance.
>
>
>
> Regards,
>
> Ali
>
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