> On Wed, 27 Apr 2011, David Laight wrote:
>
> > > But it isn't, and it doesn't have trouble with 2^32 - 1.
> >
> > what about:
> > prev = 0x00000001
> > val = 0xffffffff
>
> Result is 0xfffffffe and we are fine.
'delta' will be 0xfffffffe, but you need the function to
return zero - since the underlying counter has decremented
by 2. But 'prev > val' is false so the counter will
be increased by 2^32-2.
David
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