On 3/13/10 2:34 PM, Andrew Francis wrote:
Hi Andy:
--- On Sat, 3/13/10,
[email protected]<[email protected]> wrote:
Message: 1
Date: Fri, 12 Mar 2010 11:50:52 -0600
From: "Carl, Andrew F (AS)"<[email protected]>
To:<[email protected]>
Cc: "Carl, Andrew F \(AS\)"<[email protected]>
Subject: [Stackless] Stackless Error
Message-ID:
<[email protected]>
Content-Type: text/plain; charset="us-ascii"
Attempting to use the following:
Stackless.tasklet( self.r_run(args) )
I get the following post run error:
"TypeError: tasklet function must be a callable"
I don't know what self is. However tasklet() expects a callable (
hence the error). A while you can create a tasklet is by passing
function (a callable) to the tasklet function. The arguments are passed
separately.
example
def printIt(message):
print message
stackless.tasklet(printIt)(message)
The confusing part of this is that Andy did not call stackless.run,
so his test appears to do nothing, because the tasklet does not run at
all in the first place and gets killed when python ends.
The other approach
Stackless.tasklet( self.r_run(args) )
breaks for the reason you pointed out.
cheers - chris
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