[Default] On Thu, 11 Oct 2012 08:58:49 -0500,Paul Anderson <[email protected]> wrote:
>Using Andrew's example below, 55% divided by 15% = 3.7 times the amount >of fuel for the 3-stone fire versus the better one at 55% efficiency. > >Or 15 divided by 55 = .27 or only 27% of the fuel is used for the >55% TE stove compared to the referenced 15% TE 3-stove fire. > >These are reciprocals. 3.7 x .27 = 1.00 (precisely, it is >3.66666... x 0.2727... = 1.000000 ) > >So the better stove saves 73% of the fuel in this example. Paul, I'd avoid using percentages in this sort of illustration, it's too much like an advertising ploy and open to confusion. The simple answer to your question is that there is a direct linear relationship between fuel use and efficiency of converting the calorific value released from the fuel into heat for the pot contents.. As others have pointed out it is the difficulty in defining how to measure or agree protocols that frustrates this. Plus of course efficiency is not necessarily the most important aspect of cooking. AJH _______________________________________________ Stoves mailing list to Send a Message to the list, use the email address [email protected] to UNSUBSCRIBE or Change your List Settings use the web page http://lists.bioenergylists.org/mailman/listinfo/stoves_lists.bioenergylists.org for more Biomass Cooking Stoves, News and Information see our web site: http://www.bioenergylists.org/
