Hello everybody.
I have a following situation. There's layout.jsp and two pages: page1.jsp
and page2.jsp.
layout.jsp is simple
<s:layout-definition>
<s:layout-component name="com1">FIRST COMPONENT
<br></s:layout-component>
<s:layout-component name="com2">SECOND COMPONENT
<br></s:layout-component>
<s:layout-component name="content"/>
</s:layout-definition>
The idea is for page1.jsp to show both components (com1 and com2) and own
content.
For page2 idea is to show only com2 and not to show com1 component.
So for page1.jsp i'm doing following and it's working ok.
<s:layout-render name="/layout.jsp">
<s:layout-component name="content">PAGE1</s:layout-component>
</s:layout-render>
For page2.jsp i was going to do
<s:layout-render name="/layout.jsp">
<s:layout-component name="com1"/>
<s:layout-component name="content">PAGE2</s:layout-component>
</s:layout-render>
Since i've overriden the com1 component with empty tag i assumed the com1
won't be shown in resulting HTML.
But it is shown. To make it be hidden i needed to put some content into
layout-component tag
like this
<s:layout-component name="com1"> </s:layout-component>
But seems this is not very correct behaviour.
Can this be changed to override component declared in layout even if
content of component declared in page is empty.
--
Best Regards
Evgeny K. Shepelyuk
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