The FormFile interface doesn't give you that possebility. You can only get the InputStream to that "file". If you need an access path to a file, you have to copy the stream to another tmp file, delete (destroy) the FormFile, and pass the new created tmp file to your business object. It's a matter of the interface (the actual implementation is a DiskFile, which has a path to the server side created file. If you try to use this one, you can create code that is not compatible with future implementations of strut's upload feature). Regards, Holger -----Urspr�ngliche Nachricht----- Von: dd ss [mailto:[EMAIL PROTECTED]] Gesendet: Mittwoch, 19. September 2001 11:03 An: [EMAIL PROTECTED] Betreff: File upload : How do I access the uploaded file Hi, I want to have access to the actual file that gets uploaded and is saved on the server. i.e if a user uploads a file called test.txt and the server store this file as str345.tmp somewhere on server, how do I get access to the file str345.tmp with fully qualified path. Once I get this, I need to pass this info to another method which will extract the contents of this file and insert them in database. Because of the already existing method signature I can pass only the fully qulified file name only to the method. Thanks Vimal __________________________________________________ Terrorist Attacks on U.S. - How can you help? Donate cash, emergency relief information http://dailynews.yahoo.com/fc/US/Emergency_Information/
