Hi,
If your problem is that you need to check if that file is there or not ,
then this might help
if( getServlet().
getServletContext().getResourceAsStream(
resource ) == null ){
logger_.debug("Not found" );
} else {
logger_.debug("Found" );
}
Mohan
-----Original Message-----
From: Laurent de Menditte [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 19, 2003 4:45 PM
To: [EMAIL PROTECTED]
Subject: Problem while opening file in Action servlet
Hi,
I'm using Struts 1.1 rc1, Tomcat 4.1.18
I've written this Action class:
--------------------------------
import java.io.*;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import mypackage.API;
public class MyAction extends Action {
public ActionForward execute(ActionMapping mapping,
ActionForm form,
HttpServletRequest request,
HttpServletResponse response)
throws IOException, ServletException {
String cible = new String("success");
try {
String ConfigurationFile = "test.ini";
FileInputStream Fin = new FileInputStream(ConfigurationFile);
API api = new API();
} catch (Exception e)
{
e.printStackTrace();
}
...
return (mapping.findForward(cible));
}
}
---------------------------------
and my problem is that I catch a FileNotFoundException because the test.ini
file can't be found.
I've got the same problem while creating the API object: a configuration
file is also needed during that creation and can't be found.
How can I solve this problem?
I just want to add that I can't modify the API class, so that I can't
specify the full path of the configuration file.
Thanks for your answers.
Laurent
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