OOps! John
John L. Carmichael Jr. Sundial Sculptures 925 E. Foothills Dr. Tucson Arizona 85718 USA Tel: 520-696-1709 Email: [EMAIL PROTECTED] Website: <http://www.sundialsculptures.com> ----- Original Message ----- From: "Willy Leenders" <[EMAIL PROTECTED]> To: <[email protected]> Sent: Monday, April 15, 2002 9:56 AM Subject: Re: Sloping Analemmatics > Yes, John, doing so you peoduce the correct drawing for the sloping sundial. > But you must subtract correctly: 32.5 -3 = 29.5 > > An analemmatic sundial is the projection of a sferic equatorial sundial on a > plane. > > In the formulas of Lalande phi is the value of the latitude for the case that > the plane is horizontal (phi is then de angle between the gnonom and the > horizontal plane). But in general phi is the angle between the gnomon and the > plane on which the projection is done, in your case 29,5 degree. > > Willy Leenders > 50,9 N 5,4 E > > mailto:[EMAIL PROTECTED] > > John Carmichael wrote: > > > Hi All: > > > > I have a question. > > > > I use the Delta Cad macros to design analemmatics. These macros only permit > > the design of analemmatics that have flat horizontal faces. But I need to > > design an analemmatic that is painted on cement that slopes slightly to the > > south. Let's say the angle of slope is 3 degrees from horizontal and the > > latitude of the sundial is at 32.5 N.degrees. > > > > I thinking that if imput into the DC macro a false latitude of 32.5* - 3* = > > 31.5 degrees that it would produce the correct drawing for the sloping > > sundial. > > > > Is my thinking correct on this? > > > > Thanks anyone > > > > John > > > > John L. Carmichael Jr. > > Sundial Sculptures > > 925 E. Foothills Dr. > > Tucson Arizona 85718 > > USA > > > > Tel: 520-696-1709 > > Email: [EMAIL PROTECTED] > > Website: <http://www.sundialsculptures.com> > > > > - > > - > -
