Hi Fer

You wrote:
>But what do you want to do with it?
> I tried to find out what you may do with these average values but can't
find
> a good reason.

There's just one good reason to know the average shadow velocity of a giant
sundial like this: It's damn impressive!  25 feet per hour!  (And there are
places on the dial face where it's moving even faster) I think non-dialists
love to hear this stuff.  Especially if you say it with enthusiasm.


John

John L. Carmichael Jr.
Sundial Sculptures
925 E. Foothills Dr.
Tucson Arizona 85718
USA

Tel: 520-696-1709
Email: [EMAIL PROTECTED]
Website: <http://www.sundialsculptures.com>
----- Original Message -----
From: "fer j. de vries" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Sunday, May 26, 2002 1:04 PM
Subject: Re: Shadow Velocity Calculation?


> Hi John,
>
> Your calculation only is valuable at the summer solstice.
> At winter solstice or any other day you have to choose the daylenghth of
> that day and the lenght of the hourscale for that day.
> So you get an average for each day.
>
> But what do you want to do with it?
> Sometimes the length between 2 hour marks on your scale is longer and at
> another part it is smaller.
> So also for each hour you get different average values.
> I tried to find out what you may do with these average values but can't
find
> a good reason.
> In any case, the velocity is smallest where the scale is shortest between
a
> certain time space.
>
> Best wishes, Fer.
>
> Fer J. de Vries
> mailto:[EMAIL PROTECTED]
> http://www.iae.nl/users/ferdv/
> Eindhoven, Netherlands
> lat.  51:30 N      long.  5:30 E
>
> ----- Original Message -----
> From: "John Carmichael" <[EMAIL PROTECTED]>
> To: "Sundial List" <[email protected]>
> Sent: Saturday, May 25, 2002 5:42 PM
> Subject: Shadow Velocity Calculation?
>
>
> > Hello List:
> >
> > Would this be a true statement?
> >
> > (In this case I'm refering to the Kitt Peak Telescope Sundial, but I
think
> > it might be a true statement for any sundial):
> >
> > The average velocity of the shadow (m/hr) on the sundial face as it
moves
> > along a line connecting the time point markers is equal to the total
> length
> > of these lines (m) divided by the longest possible daylength (in hours).
> >
> > In this case that would be 118 meters /14.17 hours = 8.327 m/hr (or
> > 27ft.hr).
> >
> > John
> >
> > John L. Carmichael Jr.
> > Sundial Sculptures
> > 925 E. Foothills Dr.
> > Tucson Arizona 85718
> > USA
> >
> > Tel: 520-696-1709
> > Email: [EMAIL PROTECTED]
> > Website: <http://www.sundialsculptures.com>
> >
> > -
> >
>
> -
>

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