I've been quietly gnawing on two sundial puzzles for a while now.  And 
rather than suffer silently, a prisoner of my own inadequacies, I 
decided to 'throw myself on the mercy of the court' so to speak.

Puzzle the first.  (I'll leave the second puzzle for another day when I 
have the time to set it out with a bit of clarity...)

 

I've been wondering, idly, for about a year, after having made a mock-up 
bifilar dial, what the locus of the intersection of the N-S and E-W 
threads is, during the day, and over the course of the year.

More recently, partly inspired by the fantastic graphics on Fabio 
Savian's webpage (www.nonvedolora.it/bifilare.htm) (I finally figured 
out what a wonderful pun "non vedo lora" is; or I _think_ I have).  So.  
I got out my trigonometry books and tried to figure out what the 
equations for x and y would be.  I couldn't get Fabio's equations 2 and 
3 for x and y to work for me.

So I went back to the diagram in Fred Sawyer's article "Bifilar 
Gnomonics" _Journal of the British Astronomical Association_, Jun 1978, 
88(4):334-351. and _Bulletin of the British Sundial Society_, Feb 1993, 
93(1):36-44, also Feb 1995, 95(1):18-27. (Thanks, once again, Fred for 
sending me a copy).  After some stumbling around I derived equations for 
x and y.  And was both pleased, and mortified, to discover that Fred had 
presented the same equations later on in his article:

 

x  =  g1 sin t/(sin theta tan delta + cos theta cos t)                  
                  (10)

 

y  =  g2(sin theta cos t - cos theta tan delta)/(sin theta tan delta 
+cos theta cos t)            (11)

 

where: theta = latitude; t = solar hour angle; delta = solar 
declination; g1 is height of the thread along the y-axis (= 1/cos theta 
for a conventional bifilar dial); g2 is the height of the thread along 
the x-axis (= tan theta in the usual case).

 

I then put the equations in a spreadsheet and calculated the x and y 
coordinates for a number of hour angles during the day.  And repeated 
the exercise for different solar declinations.  I put the resulting 
coordinates into a statistics software package and plotted the results. 
(see the attached .gif which is c. 7 kb in size). (I hope the cryptic  
legend is sufficiently clear for the purposes of my question)

At first, I was quite pleased because the resulting family of curves was 
roughly what I anticipated, from my conceptualisation of the bifilar 
dial as a sort of dial cast by a vertical gnomon.  But then arose my 
puzzlement.  Although the lines though the hour marks converge to a 
point (as they should)...the angles _between_ hours are not equal.  
Hence my puzzlement.  Needless to add, I would be most grateful for an 
indication of what am I doing wrong!

warmest wishes,

Peter

-- 
Peter Mayer
Politics Department
Adelaide University, AUSTRALIA 5005
Ph    : +61 8 8303 5606
Fax   : +61 8 8303 3446
e-mail: [EMAIL PROTECTED]

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