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I've only just got around to looking into this. The
question, if you remember, was how to find the latitude and wall declination for
which a vertical sundial (such as an SGS) had been made, given that you can
measure the style height (SH) and angle between the style and vertical
(SD).
Nobody posted a correct analytical solution to
Roger Bailey's simultaneous equations, and several posters thought it had to be
done by trial and error. The thread then turned to using the hour line angles,
which is a valid approach. But there is an
easy solution. It is:
Sin
Lat = Cos SH x Cos SD
This doesn't tell us if the latitude
is north or south. An easy way to resolve this is:
In the (upper or lower) half of the dial where the gnomon is, if one
o'clock on the dial is to the right of twelve o'clock, it is for the
northern hemisphere, else for the
southern. Another way is: If the
hour lines increase clockwise, the gnomon points north, else south. If the
gnomon points up, the dial is for the same hemisphere, else the opposite
hemisphere.
Given the latitude, from my
equation above, you can find the wall declination from Roger Bailey's first
equation. To get the correct sign, make Lat positive if north, negative if
south, and measure SD anticlockwise from the vertical:
Sin
Dec = Tan SD * Tan Lat
Take the answer in the range -90 to
+90. Interpret a negative answer as a declination east of whichever pole the
gnomon is pointing to. A positive answer is a declination west of the same
pole.
For instance, if the gnomon points south, and
the equation gives Dec=-30, the wall declined 30 degrees east of
south.
Best wishes to all
Chris Lusby Taylor
51.4N
1.3W |
- Re: Reverse-engineering oldest SGS Chris Lusby Taylor
- RE: Reverse-engineering oldest SGS Roger Bailey
