On Wed, 12 Jun 2013 12:13:02 -0400
Ed Mullen <[email protected]> wrote:
> Ed Mullen wrote:
> > Lemuel Johnson wrote:
> >> Ed Mullen wrote:
> >>> Beauregard T. Shagnasty wrote:
> >>>> Ed Mullen wrote:
> >>>>
> >>>>> It's always bugged me that Google chose virtually identical
> >>>>> colors for unvisited and visited links on the results pages. I
> >>>>> tried the following
> >>>>> in userContent.css
> >>>>>
> >>>>> /* set visited link color on Google */ @-moz-document
> >>>>> domain(google.com)
> >>>>> *|*:visited:visited {
> >>>>> color:#f99 !important;
> >>>>> }
> >>>>>
> >>>>> It doesn't seem to work. I tried perusing Google's css but it
> >>>>> is an unbelievable mess to look at. Any ideas?
> >>>>
> >>>> You mean the Google search pages? Place the following rule at the
> >>>> end of
> >>>> your userContent.css file:
> >>>>
> >>>> /* set visited link color on Google, and everywhere else too */
> >>>> a:visited { color:#800080 !important; }
> >>>>
> >>>> Works for me in both SM and Firefox.
> >>>>
> >>>> You are right about Google code being a mess. Always was.
> >>>>
> >>>
> >>> I'll try that but, honestly, I've been at this issue for years and
> >>> haven't found one that works. But I'll try this. Thanks.
> >>>
> >> This works for me:
> >> @-moz-document domain(google.com) {
> >> .l:visited {
> >> color: #f00 !important;
> >> }
> >> }
> >
> > Thanks! To both BTS and Lemuel.
>
> Sorry for re-opening an old thread.
>
> The above code worked fine for some time but it no longer does. I'm
> back to Google's stupid purple for visited links.
>
> Is that style still working for anyone else?
Just using a:visited as the selector works for me, and should make it
more robust, i.e., less likely to break as Google changes things down
the road.
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