Hi Peter, You better look at a good introduction for Bezier curves: http://graphics.cs.ucdavis.edu/CAGDNotes/Bezier-Curves/Bezier- Curves.html Good luck, Samy
--- In [email protected], "pilatfr" <[EMAIL PROTECTED]> wrote: > > --- In [email protected], "hubby2debbie" > <[EMAIL PROTECTED]> wrote: > > Yes, cubic Bezier start at first point in view window, end at second > and intersection of tangent lines is the control point. > > Michel > > > If I understand you right, I need to look at where the parabola > > exits the view window, calculate the tangent lines to the parabola > > at those points, and then find the intersection of these 2 lines? > > > > Peter > > > > --- In [email protected], "pilatfr" <[EMAIL PROTECTED]> > wrote: > > > > > > --- In [email protected], "hubby2debbie" > > > <[EMAIL PROTECTED]> wrote: > > > > > > Example > > > http://pilat.free.fr/english/svg/parabole_bezier.htm > > > > > > You search intersections of parabola with canvas. Control point > is > > > intersection of tangents in this points > > > > > > Michel > > > > > > > Hi, my name is Peter, and I just found this group. I want to > > draw an > > > > accurate parabola when I have its equation. The math is no > > problem > > > for > > > > me, I just need to know how to find the control point for the > > > quadratic > > > > curve. Actually, I can figure out the x-coordinate of the > point, > > but > > > > I'm not sure how to figure out the y-coordinate. Any help > would > > be > > > > appreciated. > > > > > > > > Peter ----- To unsubscribe send a message to: [EMAIL PROTECTED] -or- visit http://groups.yahoo.com/group/svg-developers and click "edit my membership" ---- Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/svg-developers/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
