Hi Andreas,
I am Jacky, I am currently dealing with a web map SVG based
project, sounds similiar to the work of your project. I studies your
project, including this one and the example 5.
I studied quite deeply in the example 5, but I encountered some
conceptual problem while studying the query part. May I raise a
question here? I just would like to make clear how does the work of
the function "intersection" and what exactly the semantic is about
the query?
Since, as my understanding, the query is
Select AsSVG(Intersection(Simplify(g, $), geomfromtext(the bbox of
the new view)..) From ... Where g && setSRID(new view box-the same as
the one in select sub clause) and level...
The semantic is to select the new view box geometry, then simplify
it as the result intersec with its own view box. How can this query
finish the job just querying the missing part of map data when you pan
the map? That is, the old view box overlaps with the new view box, the
example query only the missing part, in my understanding, the query
seems not completely done the job...(or something I missed?)
In my own understanding, I will do like, just query the missing two
rectangle when the two view box overlap in this case, but not that
easy as you done in example 5. Sorry for my miss understanding
somewhere, I do know that I must miss the important part, so that I
raise the question here, hope you don't mind....^.^
Looking forward to your reply!!
Have a nice day~~
Jacky
--- In [email protected], "Andreas Neumann"
<[EMAIL PROTECTED]> wrote:
>
> Hi all,
>
> As you might have noticed, there is a Photo Gallery in the Yosemite
> Mapping Application (http://www.carto.net/williams/yosemite/) - we are
> still looking for more photos of the National Park, esp. from the more
> remote places. If you want to contribute to the photo-gallery please
> contact Juliana or me. Ideally you know the coordinates and direction
> where you took the photo, so we could geo-reference the photo in the
> map. We can't pay you for the photos, but your name will appear next
> to the photo and you still own the copyright.
>
> Thanks for your help and all the best,
> Andreas
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