Randy & M.

I'm sightly embarrassed - the light finally came on. Thanks to both of
you for your replies. I guess was hoping someone had created a routine
 that I could pass in an arbitrary path along with my single point and
I would get back a simple in or out. Looks like I will actually have
to create something that looks at each segment of the path by segment
type (h,v,l,c, etc.) and see if my vector intersects. 

Thanks again,
Jeff E.  

--- In [email protected], "Randy George" <[EMAIL PROTECTED]>
wrote:
>
> Hi,
> 
>       Sorry in advance if I'm misunderstanding the problem. Svg paths can
> often be made into closed paths by making sure to add the 1st vertex
to the
> end. 
> 
>       From an algorithm point of view there are lots of sites that have
> information. Here is a discussion chosen at random from a google search:
> http://www.acm.org/pubs/tog/editors/erich/ptinpoly/
> 
> The basic idea (after closing the path) is to draw a ray from the
point in
> question to infinity(or just very large relative to the path space)
and then
> count the number of times the line intersects a segment of the
closed path.
> If the count is odd the point is inside if even not.
> 
>       Although, you might be inside a hole (Moveto) which could be
> considered inside an outer ring, but outside the inner ring and thus
outside
> the multi ring. If a closed path is self intersecting life is equally
> complicated, so that self-intersection is generally defined away by
> preconditioning into multiple paths. .. and we haven't even brought up
> correct intersection of cubic Bezier curve segments.
> 
> Here is the classic Java api for geometric calcs:
> http://www.vividsolutions.com/jts/jtshome.htm - LPGL
> 
> Randy
> 
> <?xml version="1.0" standalone="no"?>
> <!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 20001102//EN"
>   "http://www.w3.org/TR/SVG/DTD/svg10.dtd"; >
> <svg 
>       xmlns:xlink="http://www.w3.org/1999/xlink";
>       xmlns="http://www.w3.org/2000/svg";
>       width="600" height="600"
>       preserveAspectRatio="xMinYMin"
>       viewBox="5.317441 -30.263707 7.082269240963304 28.294216539175043"
> >
>       <path style="fill:white;stroke:black;stroke-width:0.1"
> d="M11.3315706,-9.81481061 L12.39971036,-9.76838859
L11.70309752,-7.77224211
> L10.26343073,-8.93279238 L11.37801148,-8.93279238
L7.61630154,-10.46471881
> L9.10240909,-11.253893 L9.79902205,-10.04692071
L10.58851676,-13.29646157
> L12.02818356,-12.55370933 L10.77428016,-11.71811312
> L11.65665664,-11.30031502 L11.19224796,-10.46471881
L11.3315706,-9.81481061
> "/>
>       <line style="stroke:red;stroke-width:0.1" x1="10.449194"
> y1="-10.603984" x2="5.433580" y2="-10.603984"/>
> </svg>
> 
> 
> -----Original Message-----
> From: [email protected]
[mailto:[EMAIL PROTECTED]
> On Behalf Of rs274d
> Sent: Friday, January 19, 2007 8:20 AM
> To: [email protected]
> Subject: [svg-developers] Re: Need help determining if a point is
inside or
> outside of a closed path
> 
> --- In [email protected], "vmmdragon" <vmmdragon@> wrote:
> >
> > --- In [email protected], "rs274d" <jge14@> wrote:
> > >
> > > Can anyone someone guide me in determining if a point is inside or
> > > outside of a closed path? I can manage this for polygons but I'm
lost
> > > where to start on paths. Alternatively has someone written code they
> > > would share on converting paths to polygons? Any help is much
> > appreciated.
> > > 
> > > Thanks,
> > > 
> > > Jeff E.
> > >
> > 
> > Take a look at http://kevlindev.com/geometry/
> > he's got a great working SVG example.
> > 
> > M.
> >
> M.
> 
> Thanks for the pointer -  but I could not find an example of
> determining if a point is inside or outside of a path. Lots of
> examples of intersection with paths and an example of a point in a
> polygon. 
> 
> What I'm trying to do is determine if a point (start of a piece of
> text) in layer 1 is inside or outside of a several paths (mixed
> absolute and relative) on layer 2. 
> 
> I have this working great if layer 2 containing polygons but I am
> struggling for a way to do the same with paths.
> 
> Many Thanks,
> Jeff E.
> 
> 
> 
> 
> 
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