You can figure it out by testing each segment of the rect against the line
for intersection. Then test the intersection is within the bounding box of
the rect.
This function came from carto.net:
function
intersect2lines(line1x1,line1y1,line1x2,line1y2,line2x1,line2y1,line2x2,line2y2)
{
//formula see http://astronomy.swin.edu.au/~pbourke/geometry/lineline2d/
var result = new Array();
var denominator = (line2y2 - line2y1)*(line1x2 - line1x1) - (line2x2 -
line2x1)*(line1y2 - line1y1);
if (denominator == 0) {
alert("lines are parallel");
}
else {
ua = ((line2x2 - line2x1)*(line1y1 - line2y1) - (line2y2 -
line2y1)*(line1x1 - line2x1)) / denominator;
ub = ((line1x2 - line1x1)*(line1y1 - line2y1) - (line1y2 -
line1y1)*(line1x1 - line2x1)) / denominator;
}
result["x"] = line1x1 + ua * (line1x2 - line1x1);
result["y"] = line1y1 + ua * (line1y2 - line1y1);
return(result);
}
Stephen
On 5/10/07, shydisturbedboy <[EMAIL PROTECTED]> wrote:
>
> let's say we have a line and a rect. the line passes through the rect.
> how will it know that the line intersected with the box?
>
>
>
[Non-text portions of this message have been removed]
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