Thanks for the help has been very useful

--- In [email protected], John Delacour <j...@...> wrote:
>
> At 11:46 +0000 20/10/10, fi...@... wrote:
> 
> >Anybody can help me with svg rect convertion to svg path? I need 
> >know the steps to convert rect parameters to path commands.
> >
> >Example, I have:
> >
> >rect:
> >height 2.8569181
> >width 90.898613
> >x 20.280216
> >y 838.27399
> >rx 0.9670065
> >ry 1.2499017
> >
> >Inkscape make this:
> >
> >m 21.247223,838.27399 88.964597,0 c 0.53572,0 0.96701,0.55745 
> >0.96701,1.2499 l 0,0.35711 c 0,0.69245 -0.43129,1.2499 
> >-0.96701,1.2499 l -88.964597,0 c -0.535722,0 -0.967007,-0.55745 
> >-0.967007,-1.2499 l 0,-0.35711 c 0,-0.69245 0.431285,-1.2499 
> >0.967007,-1.2499 z
> >
> >My problem is with c command control points.
> 
> You are dealing here not with curves but elliptical arcs, so the 
> maths is extremely simple.  Here's a perl script that does the job 
> and should be self-explanatory.  Where you actually start the path is 
> up to you.
> 
> 
> #!/usr/bin/perl
> use strict;
> # Rectangle
> my $height = 2.8569181;
> my $width = 90.898613;
> my $x = 20.280216;
> my $y = 838.27399;
> my $rx = 0.9670065;
> my $ry = 1.2499017;
> # My dims
> my $mx = $x;
> my $my = $y + $ry;
> my $v = $height - 2 * $ry;
> my $h = $width - 2 * $rx;
> # Print path
> print "<path d=\"" .
> "m $mx $my " .
> "v $v " .
> "a $rx $ry 0 0 0 $rx $ry " .
> "h $h " .
> "a $rx $ry 0 0 0 $rx -$ry " .
> "v -$v " .
> "a $rx $ry 0 0 0 -$rx -$ry " .
> "h -$h " .
> "a $rx $ry 0 0 0 -$rx $ry" .
> "\" />";
> 
> RESULT:
> <path d="m 20.280216 839.5238917 v 0.3571147 a 0.9670065 1.2499017 0 
> 0 0 0.9670065 1.2499017 h 88.9646 a 0.9670065 1.2499017 0 0 0 
> 0.9670065 -1.2499017 v -0.3571147 a 0.9670065 1.2499017 0 0 0 
> -0.9670065 -1.2499017 h -88.9646 a 0.9670065 1.2499017 0 0 0 
> -0.9670065 1.2499017" />
> 
> JD
>




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