On Thu, 27 Aug 2015, Xin LI wrote:
Log: die() would never return, mark it as so.
Why? (Except to add a style bug.)
Modified: head/usr.sbin/syslogd/syslogd.c ============================================================================== --- head/usr.sbin/syslogd/syslogd.c Thu Aug 27 17:16:18 2015 (r287216) +++ head/usr.sbin/syslogd/syslogd.c Thu Aug 27 18:11:00 2015 (r287217) @@ -324,7 +324,7 @@ static const char *cvthname(struct socka static void deadq_enter(pid_t, const char *); static int deadq_remove(pid_t); static int decode(const char *, const CODE *); -static void die(int); +static void die(int) __dead2;
Since the function is static, it is very easy for the compiler to see that it doesn't return. Even gcc-4.2.1 does this by default, since -O implies -funit-at-a-time for gcc-4.2.1. For clang, there is no way to prevent this (except possibly -O0) since, since -fno-unit-at-a-time is broken in clang. Several other functions in the same file are still missing this style bug: - usage(). The style bug is clearly documented for usage() by its absence in style(9) and in most files that have usage(). Howvever, about 30 declarations of usage() in /usr/src have the style bug. - timedout(). This is a signal handler, so doesn't really need it. This is broken signal handler. It carefully uses _exit() so as to not use stdio in a signal handler, but defeats this by also using errx(). Bruce _______________________________________________ svn-src-all@freebsd.org mailing list https://lists.freebsd.org/mailman/listinfo/svn-src-all To unsubscribe, send any mail to "svn-src-all-unsubscr...@freebsd.org"
