Hi, Would be really helpful, if you can elaborate it a bit. How do i create the 'schema object' which you mentioned?
On Thursday, 1 June 2017 20:28:40 UTC+5:30, 杨佳欢 wrote: > > Hi Chenbaga, > > you should create a schema object under the parameter. > > Jan > > 在 2017年6月1日星期四 UTC+2上午10:48:28，Chenbaga Murugan写道： >> >> >> <https://lh3.googleusercontent.com/-irK51T1cz24/WS_UmbFeAGI/AAAAAAAAQZM/xzgxg6f59aUfaz9zt-EvP9S9EWrhqJkSgCLcB/s1600/Screen%2BShot%2B2017-06-01%2Bat%2B1.50.36%2BPM.png> >> Hi All, >> >> I am using Swagger UI to document my REST API developed in Jersey + >> SpringBoot. I would like to provide sample JSON body for one of my POST >> endpoint. The json has various fields ranging from Date, String, Enums >> etc.. What is the right way to populate the body with a sample JSON, with >> some default values for all the fields. When the 'Try Out' button is >> clicked, the request should directly work with the sample input. >> >> Attaching the screenshot of one such service, where i came across. I am >> not sure how to achieve the same in my service. >> >> >> <https://lh3.googleusercontent.com/-irK51T1cz24/WS_UmbFeAGI/AAAAAAAAQZM/xzgxg6f59aUfaz9zt-EvP9S9EWrhqJkSgCLcB/s1600/Screen%2BShot%2B2017-06-01%2Bat%2B1.50.36%2BPM.png> >> Thanks >> Chenbaga >> > -- You received this message because you are subscribed to the Google Groups "Swagger" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
