Which library do you use to generate the API definition?
From: <[email protected]> on behalf of Gökhan Ayrancıoğlu <[email protected]> Reply-To: "[email protected]" <[email protected]> Date: Tuesday, November 14, 2017 at 01:59 To: Swagger <[email protected]> Subject: How to define abstract property in Model - Swagger I am trying to implement Swagger to my rest api which is development with Java Spring Boot. There is a problem on model parts of swagger. The problem is Detail abstract class and extended classes are not seem in Swagger UI's and the other output files. I am just seeing the baseclass with detail object as null. You can find the code on below. public class BaseClass { @ApiModelProperty(value ="Id of baseClass.", readOnly = true) private String id; @ApiModelProperty(value = "Description of baseClass.") private String description; @ApiModelProperty(value = "Value is equal to subclass json object value.") private Detail detail; ... My abstract class which is attribute of baseclass. @ApiModel(value = "Detail",subTypes = {Page.class,Rank.class},discriminator = "detail") public abstract class Detail { } My extended classes from Detail Abstract Class; Page Class: @ApiModel(parent = Detail.class,value = "Page") public class Page extends Detail { @ApiModelProperty(value = "The page URL.") private String url; ... Rank Class: @ApiModel(parent = Detail.class,value = "Rank") public class Rank extends Detail { @ApiModelProperty(value = "Number List of Rank") private List<String> numbers; ... -- You received this message because you are subscribed to the Google Groups "Swagger" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups "Swagger" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
