Since I’m not 100% sure, filing a ticket would be the best way to get an answer.
From: <swagger-swaggersocket@googlegroups.com> on behalf of Frank Rosenberger
<rosenberg...@gmail.com>
Reply-To: "swagger-swaggersocket@googlegroups.com"
<swagger-swaggersocket@googlegroups.com>
Date: Friday, March 9, 2018 at 00:05
To: Swagger <swagger-swaggersocket@googlegroups.com>
Subject: Re: JAXB annotated non-public fields
Yeah, but first I wanted to make sure if that is really something which is not
supported or if I just couldn't find how to do it. The documentation seemed
unclear to me.
On Thursday, March 8, 2018 at 7:31:51 PM UTC+1, Ron wrote:
I’d suggest filing a ticket with the respective project.
From: <swagger-sw...@googlegroups.com> on behalf of Frank Rosenberger
<rosenb...@gmail.com>
Reply-To: "swagger-sw...@googlegroups.com" <swagger-sw...@googlegroups.com>
Date: Thursday, March 8, 2018 at 03:30
To: Swagger <swagger-sw...@googlegroups.com>
Subject: JAXB annotated non-public fields
I am using Swagger 3.0/Open-API in a Java project.
I have non-bean-like DTO classes which are JAX-B-annotated.
@XmlType
@XmlAccessorType(XmlAccessType.FIELD)
public MyDTO {
private String myProperty;
}
Swagger does not pick up the property myProperty while JAX-B and Jackson
process it as expected.
The Swagger docs talk about bean properties from time to time, but I don't see
a requirement for classes to be beans. All solutions regarding JAXB and
non-bean-like model classes I found (e.g. @ApiModelProperty) refer to older
Swagger versions.
Is there a way to have current Swagger process non-public properties without
setters/getters?
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