On Fri, Dec 4, 2015 at 10:00 PM, Andrew Trick <atr...@apple.com> wrote: > I’m adding runtime functionality to support optional casts and ran into some > Optional to String conversion behavior that is currently somewhat > accidental—it will break when I add functionality. I want to understand the > desired behavior before doing extra work to fix it. > > Currently swift does this: > >> print(Int?(3)) > Optional(3) >> print(String?("meow")) > Optional("meow") > > I think swift should do this: > >> print(Int?(3)) > 3 >> print(String?("meow")) > "meow" >> debugPrint(Int?(3)) > Optional(3) >> debugPrint(String?("meow")) > Optional("meow") > > When a value already knows how to represent itself as a string, I don't think > that the string "Optional" belongs in the textual representation. > > When debugging data structures, it makes sense to include the "Optional" > indicator. > > What was the intention here and what do people think is the desired behavior?
This behavior was not accidental. Here's the rationale: If an Optional is nil, it should somehow indicate that. Whatever the representation is, it would be engineer-oriented and not suitable for end users. Thus, Optional should never be printed to users, it would only ever be presented to engineers, and thus its print() and debugPrint() representations should be the same. Dmitri -- main(i,j){for(i=2;;i++){for(j=2;j<i;j++){if(!(i%j)){j=0;break;}}if (j){printf("%d\n",i);}}} /*Dmitri Gribenko <griboz...@gmail.com>*/ _______________________________________________ swift-dev mailing list swift-dev@swift.org https://lists.swift.org/mailman/listinfo/swift-dev