> On Dec 16, 2015, at 11:24 AM, Kevin Ballard via swift-dev 
> <swift-dev@swift.org> wrote:
> 
> On Wed, Dec 16, 2015, at 12:12 AM, Dave Abrahams wrote:
>> 
>>> Come to think of it, what's the actual use-case for withUnsafePointer()?
>> 
>> I'm not sure we still have one that isn't covered by &x; that's my point.
>> 
>>> If a value is mutable, you can already use &x or 
>>> withUnsafeMutablePointer(), and if it's immutable, you can't call 
>>> withUnsafePointer() today anyway. The proposed change would just make 
>>> withUnsafePointer() into the equivalent of `var x = value; 
>>> callSomethingWith(&x)`. The only reason to really want a 
>>> withUnsafePointer() function is if it can give you an UnsafePointer to an 
>>> immutable value without copying it, but we can't do that. I'm inclined to 
>>> say we should just get rid of withUnsafePointer() entirely, at least until 
>>> such time as Swift has a way to pass immutable values by-ref.
>> 
>> I'm inclined to agree.  Proposal?
> 
> Sure, I'll write one up. I suspect that withUnsafePointer() / 
> withUnsafeMutablePointer() are likely to be rarely used today, and most uses 
> can probably be trivially replaced with just passing a &x ref, so this 
> shouldn't be a big deal.

We can't remove withUnsafe[Mutable]Pointer; as I mentioned to Dave, it's 
necessary to persist a pointer for more than one immediate call.

> 
> I'll also go ahead and write up one suggesting that we should allow for using 
> &x when x is immutable when passing a parameter to a function that takes 
> UnsafePointer.

That would be useful, though I would argue that the '&' shouldn't be necessary. 
We aren't C; '&x' means "this call mutates x", not "I'm taking a pointer to x".

-Joe
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