> On Mar 16, 2017, at 4:23 PM, Joe Groff <jgr...@apple.com> wrote:
>> On Mar 14, 2017, at 3:53 PM, Greg Parker via swift-dev <swift-dev@swift.org> 
>> wrote:
>> 
>>> 
>>> On Mar 14, 2017, at 2:16 PM, John McCall <rjmcc...@apple.com> wrote:
>>> 
>>>> On Mar 14, 2017, at 5:08 PM, Jordan Rose via swift-dev 
>>>> <swift-dev@swift.org> wrote:
>>>> 
>>>>> On Mar 14, 2017, at 13:52, Greg Parker via swift-dev 
>>>>> <swift-dev@swift.org> wrote:
>>>>> 
>>>>>> On Mar 14, 2017, at 1:34 PM, Greg Parker via swift-dev 
>>>>>> <swift-dev@swift.org> wrote:
>>>>>> 
>>>>>>> On Mar 14, 2017, at 12:43 PM, Joe Groff <jgr...@apple.com> wrote:
>>>>>>> 
>>>>>>> Hey Greg, what are the correct refcounting bits now to set in a global 
>>>>>>> statically-emitted heap object that shouldn't ever be released?
>>>>>> 
>>>>>> For now use the same thing that stack-allocated objects use. I forget 
>>>>>> what the bit pattern is exactly. (I assume you are not in strictly 
>>>>>> read-only memory and can tolerate writes to the refcount word. We don't 
>>>>>> yet have an implementation for immortal read-only objects.)
>>>>> 
>>>>> Oh wait, you *don't* want to use what stack-allocated objects use. They 
>>>>> get deinited without being deallocated, and I assume you want neither 
>>>>> deinit nor dealloc. Let me work this out.
>>>> 
>>>> Wouldn’t it be okay to just emit it with an unbalanced retain?
>>> 
>>> It's better if there's some way to make an object completely ref-count 
>>> inert.  Often, the compiler only sees one side of a retain/release pair, 
>>> like when you return a constant NSString — you know locally that you're 
>>> retaining a constant string, but you're returning it to some context that 
>>> has no idea what it's getting.  If the object is just unbalanced-retained, 
>>> you have to preserve the retain or else the caller might release it.  
>>> (That's true even if the imbalance is quite large — no fair crashing the 
>>> program but only after a function's been called 2^19 times!  Imagine 
>>> reproducing that...) Making the object completely inert means you can just 
>>> unconditionally say "hey, I know R/R are no-ops on this value" and delete 
>>> them as a peephole.
>> 
>> That's right. Unbalanced retain is the solution today. I expect a truly 
>> inert solution soon.
> 
> Cool. Do you think we'd be able to avoid atomic barriers on inert objects, or 
> would that unfairly impact freeable objects?

Greg is the right person to answer this for certain, but retain and release use 
a load + exchange pattern, and inertness will presumably be testable based 
purely on the initial load.

John.
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