Well, that's just it. $ is a perfectly valid character in identifiers everywhere but in the grammar for operators for some reason. It isn't reserved, it just isn't there.
~Robert Widmann 2016/01/03 0:53、Brent Royal-Gordon <[email protected]> のメッセージ: >> Swift currently does not allow operators to use $ - I assume because the >> grammar reserves it in one place: `implicit-parameter-name`. I don't see >> why an entire class of identifiers has been eliminated, so I propose $ >> instead be reclassified as an `operator-character` so it can be used mixed >> in with other such characters, but prevents the introduction of >> `$Identifier`-style declarations that might conflict with implicit >> parameters. > > I believe the reason you don't see any other $ variables is that they're > reserved for the debugger and REPL. > > brent@Brents-MacBook-Pro ~/D/Code> swift > Welcome to Apple Swift version 2.1.1 (swiftlang-700.1.101.15 > clang-700.1.81). Type :help for assistance. > 1> "foo" > $R0: String = "foo" > 2> print($R0) > foo > > -- > Brent Royal-Gordon > Architechies > _______________________________________________ swift-evolution mailing list [email protected] https://lists.swift.org/mailman/listinfo/swift-evolution
