In this particular case I belive
func foo(int: Int) -> (Int) -> (String) -> String
is much more explicit and clear about what is what :
foo(int: Int) returns not Int(that returns then String and then String).
foo(int: Int) return function with (Int) parameter, that return func with
(String) parameter that returns single String value.
On 20.04.2016 20:53, Chris Lattner via swift-evolution wrote:
On Apr 20, 2016, at 8:46 AM, BJ Homer <[email protected]> wrote:
How would this proposal affect curried functions? Would this:
func foo(int: Int) -> Int -> String -> String
become this?
func foo(int: Int) -> (((Int) -> String) -> String)
No, it becomes:
func foo(int: Int) -> (Int) -> (String) -> String
-Chris
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