Jaden,

In that very specific example with generics, couldn't you just explicitly
specify foo<[T]>(bar: bar)?

On Fri, May 20, 2016 at 12:39 PM <[email protected]> wrote:

> Without it, there could be ambiguity. Observe:
>
> func foo<T>(bar: [T]...) {
>   foo(bar: bar) // splat or pass single arg?
> }
>
> - Jaden Geller
> Sent from my iPhone
>
> On May 20, 2016, at 9:29 AM, Christopher Boyd via swift-evolution <
> [email protected]> wrote:
>
> Vladimir,
>
> True, but does the extra syntax actually accomplish anything?
>
> From my example:
>
>    - func arithmeticMean(numbers: Double...) -> Double {
>    - return add(numbers) / Double(numbers.count)
>    - }
>
>
> It's clear that the intent is to pass all the numbers to add().
>
> What, exactly, does adding the #splat() syntax achieve?  It doesn't add
> any additional clarity.
>
> Moreover, I don't think #splat has been accepted as a proposal yet.
>
> On Fri, May 20, 2016 at 12:19 PM Vladimir.S <[email protected]> wrote:
>
>> [offtopic]
>> On 20.05.2016 19:08, Christopher Boyd via swift-evolution wrote:
>> > Certainly, #splat would work, but it may be slightly more confusing to
>> > someone that hasn't seen the splat operator before:
>> So, he/she will open swift documentation or drop the question to google
>> once, and from that moment will know what #splat means.
>> [/offtopic]
>>
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