I'm not sure what enhancing defaults would look like, especially for protocols. Are you suggesting if there's a protocol like:
protocol A { func requiredFunction(a, b, c) -> T } that you could then extend extension A { func requiredFunction(a, b = somedefault, c) -> T; } as a declaration without an implementation? -- E > On Jun 13, 2016, at 2:17 AM, Haravikk via swift-evolution > <swift-evolution@swift.org> wrote: > > As Charlie says the default value may not actually be public. > > There was a thread a while ago about allowing defaults to be defined in > protocols, but I don’t think it ever got made into a proposal; this would be > useful however in cases where you want a consistent, known default. Either > that or you need the option of declaring a default value as public perhaps? > >> On 11 Jun 2016, at 14:35, Adrian Zubarev via swift-evolution >> <swift-evolution@swift.org <mailto:swift-evolution@swift.org>> wrote: >> >> I just installed the current Swift 3 snapshot to play around with it (last >> from may crashed my Xcode all the time). >> >> I wanted to re-build a small project with (currently implemented) Swift 3 >> changes. Basically I had to look up on GitHub what the default value for >> deinitialize(count:) function was for UnsafeMutablePointer, just because >> Xcode and the docs can’t tell me that: >> >> /// De-initialize the `count` `Pointee`s starting at `self`, returning >> /// their memory to an uninitialized state. >> /// >> /// - Precondition: The `Pointee`s at `self..<self + count` are >> /// initialized. >> /// >> /// - Postcondition: The memory is uninitialized. >> public func deinitialize(count: Int = default) >> To cut it short: >> >> Could we make default function parameter values more transparent in Swift 3? >> Why are default parameter values translated to default rather than the >> actual value? >> Can we make this independent from docs?
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